There were some coins in Bag M and Bag N. After Neave transferred
14 of the coins from Bag M to Bag N, the ratio of the number of coins in Bag M to that in Bag N changed to 2 : 3. Find the ratio of the numbers of coins in Bag M to the number of coins in Bag N at first.
|
Bag M |
Bag N |
Before |
4x2 = 8 u |
7 u |
Change |
- 1x2 = - 2 u |
+ 2 u |
After |
3x2 = 6 u |
|
Comparing Bag M and Bag N in the end |
2x3 = 6 u |
3x3 = 9 u |
The number of coins in Bag M in the end is repeated. Make the number of coins in Bag M in the end the same. LCM of 3 and 2 is 6.
At first
Bag M : Bag N
8 : 7
Answer(s): 8 : 7