There were some beads in Box T and Box U. After Vincent transferred
15 of the beads from Box T to Box U, the ratio of the number of beads in Box T to that in Box U changed to 1 : 8. Find the ratio of the numbers of beads in Box U to the number of beads in Box T at first.
| |
Box T |
Box U |
| Before |
5x1 =
5 u |
31 u |
| Change |
- 1x1 =
- 1 u |
+ 1 u |
| After |
4x1 =
4 u |
|
Comparing Box T and
Box U in the end |
1x4 =
4 u |
8x4 =
32 u |
The number of beads in Box T in the end is repeated. Make the number of beads in Box T in the end the same. LCM of 4 and 1 is 4.
At first
Box U : Box T
31: 5
Answer(s): 31: 5
