There were some beads in Packet M and Packet N. After Julian transferred
14 of the beads from Packet M to Packet N, the ratio of the number of beads in Packet M to that in Packet N changed to 2 : 3. Find the ratio of the numbers of beads in Packet N to the number of beads in Packet M at first.
|
Packet M |
Packet N |
Before |
4x2 = 8 u |
7 u |
Change |
- 1x2 = - 2 u |
+ 2 u |
After |
3x2 = 6 u |
|
Comparing Packet M and Packet N in the end |
2x3 = 6 u |
3x3 = 9 u |
The number of beads in Packet M in the end is repeated. Make the number of beads in Packet M in the end the same. LCM of 3 and 2 is 6.
At first
Packet N : Packet M
7: 8
Answer(s): 7: 8