There were some pens in Packet X and Packet Y. After Peter transferred
13 of the pens from Packet X to Packet Y, the ratio of the number of pens in Packet X to that in Packet Y changed to 3 : 5. Find the ratio of the numbers of pens in Packet Y to the number of pens in Packet X at first.
|
Packet X |
Packet Y |
Before |
3x3 = 9 u |
7 u |
Change |
- 1x3 = - 3 u |
+ 3 u |
After |
2x3 = 6 u |
|
Comparing Packet X and Packet Y in the end |
3x2 = 6 u |
5x2 = 10 u |
The number of pens in Packet X in the end is repeated. Make the number of pens in Packet X in the end the same. LCM of 2 and 3 is 6.
At first
Packet Y : Packet X
7: 9
Answer(s): 7: 9