There were some beads in Packet V and Packet W. After Tim transferred
25 of the beads from Packet V to Packet W, the ratio of the number of beads in Packet V to that in Packet W changed to 1 : 5. Find the ratio of the numbers of beads in Packet W to the number of beads in Packet V at first.
|
Packet V |
Packet W |
Before |
5x1 = 5 u |
13 u |
Change |
- 2x1 = - 2 u |
+ 2 u |
After |
3x1 = 3 u |
|
Comparing Packet V and Packet W in the end |
1x3 = 3 u |
5x3 = 15 u |
The number of beads in Packet V in the end is repeated. Make the number of beads in Packet V in the end the same. LCM of 3 and 1 is 3.
At first
Packet W : Packet V
13: 5
Answer(s): 13: 5