There were some coins in Packet U and Packet V. After Dylan transferred
35 of the coins from Packet U to Packet V, the ratio of the number of coins in Packet U to that in Packet V changed to 1 : 8. Find the ratio of the numbers of coins in Packet V to the number of coins in Packet U at first.
|
Packet U |
Packet V |
Before |
5x1 = 5 u |
13 u |
Change |
- 3x1 = - 3 u |
+ 3 u |
After |
2x1 = 2 u |
|
Comparing Packet U and Packet V in the end |
1x2 = 2 u |
8x2 = 16 u |
The number of coins in Packet U in the end is repeated. Make the number of coins in Packet U in the end the same. LCM of 2 and 1 is 2.
At first
Packet V : Packet U
13: 5
Answer(s): 13: 5