There were some erasers in Bag T and Bag U. After Riordan transferred
25 of the erasers from Bag T to Bag U, the ratio of the number of erasers in Bag T to that in Bag U changed to 2 : 5. Find the ratio of the numbers of erasers in Bag U to the number of erasers in Bag T at first.
|
Bag T |
Bag U |
Before |
5x2 = 10 u |
11 u |
Change |
- 2x2 = - 4 u |
+ 4 u |
After |
3x2 = 6 u |
|
Comparing Bag T and Bag U in the end |
2x3 = 6 u |
5x3 = 15 u |
The number of erasers in Bag T in the end is repeated. Make the number of erasers in Bag T in the end the same. LCM of 3 and 2 is 6.
At first
Bag U : Bag T
11: 10
Answer(s): 11: 10