There were some coins in Packet M and Packet N. After Sam transferred
14 of the coins from Packet M to Packet N, the ratio of the number of coins in Packet M to that in Packet N changed to 1 : 4. Find the ratio of the numbers of coins in Packet N to the number of coins in Packet M at first.
|
Packet M |
Packet N |
Before |
4x1 = 4 u |
11 u |
Change |
- 1x1 = - 1 u |
+ 1 u |
After |
3x1 = 3 u |
|
Comparing Packet M and Packet N in the end |
1x3 = 3 u |
4x3 = 12 u |
The number of coins in Packet M in the end is repeated. Make the number of coins in Packet M in the end the same. LCM of 3 and 1 is 3.
At first
Packet N : Packet M
11: 4
Answer(s): 11: 4