There were some coins in Packet M and Packet N. After Vincent transferred
25 of the coins from Packet M to Packet N, the ratio of the number of coins in Packet M to that in Packet N changed to 1 : 8. Find the ratio of the numbers of coins in Packet N to the number of coins in Packet M at first.
|
Packet M |
Packet N |
Before |
5x1 = 5 u |
22 u |
Change |
- 2x1 = - 2 u |
+ 2 u |
After |
3x1 = 3 u |
|
Comparing Packet M and Packet N in the end |
1x3 = 3 u |
8x3 = 24 u |
The number of coins in Packet M in the end is repeated. Make the number of coins in Packet M in the end the same. LCM of 3 and 1 is 3.
At first
Packet N : Packet M
22: 5
Answer(s): 22: 5