There were some beads in Packet C and Packet D. After George transferred
45 of the beads from Packet C to Packet D, the ratio of the number of beads in Packet C to that in Packet D changed to 2 : 9. Find the ratio of the numbers of beads in Packet C to the number of beads in Packet D at first.
|
Packet C |
Packet D |
Before |
5x2 = 10 u |
1 u |
Change |
- 4x2 = - 8 u |
+ 8 u |
After |
1x2 = 2 u |
|
Comparing Packet C and Packet D in the end |
2x1 = 2 u |
9x1 = 9 u |
The number of beads in Packet C in the end is repeated. Make the number of beads in Packet C in the end the same. LCM of 1 and 2 is 2.
At first
Packet C : Packet D
10 : 1
Answer(s): 10 : 1