There were some pens in Packet M and Packet N. After Riordan transferred
25 of the pens from Packet M to Packet N, the ratio of the number of pens in Packet M to that in Packet N changed to 1 : 7. Find the ratio of the numbers of pens in Packet N to the number of pens in Packet M at first.
|
Packet M |
Packet N |
Before |
5x1 = 5 u |
19 u |
Change |
- 2x1 = - 2 u |
+ 2 u |
After |
3x1 = 3 u |
|
Comparing Packet M and Packet N in the end |
1x3 = 3 u |
7x3 = 21 u |
The number of pens in Packet M in the end is repeated. Make the number of pens in Packet M in the end the same. LCM of 3 and 1 is 3.
At first
Packet N : Packet M
19: 5
Answer(s): 19: 5