There were some coins in Packet Y and Packet Z. After Charlie transferred
14 of the coins from Packet Y to Packet Z, the ratio of the number of coins in Packet Y to that in Packet Z changed to 1 : 8. Find the ratio of the numbers of coins in Packet Y to the number of coins in Packet Z at first.
|
Packet Y |
Packet Z |
Before |
4x1 = 4 u |
23 u |
Change |
- 1x1 = - 1 u |
+ 1 u |
After |
3x1 = 3 u |
|
Comparing Packet Y and Packet Z in the end |
1x3 = 3 u |
8x3 = 24 u |
The number of coins in Packet Y in the end is repeated. Make the number of coins in Packet Y in the end the same. LCM of 3 and 1 is 3.
At first
Packet Y : Packet Z
4 : 23
Answer(s): 4 : 23