There were some coins in Box H and Box J. After Daniel transferred
23 of the coins from Box H to Box J, the ratio of the number of coins in Box H to that in Box J changed to 2 : 5. Find the ratio of the numbers of coins in Box J to the number of coins in Box H at first.
| |
Box H |
Box J |
| Before |
3x2 =
6 u |
1 u |
| Change |
- 2x2 =
- 4 u |
+ 4 u |
| After |
1x2 =
2 u |
|
Comparing Box H and
Box J in the end |
2x1 =
2 u |
5x1 =
5 u |
The number of coins in Box H in the end is repeated. Make the number of coins in Box H in the end the same. LCM of 1 and 2 is 2.
At first
Box J : Box H
1: 6
Answer(s): 1: 6
