There were some beads in Box L and Box M. After Charlie transferred
35 of the beads from Box L to Box M, the ratio of the number of beads in Box L to that in Box M changed to 1 : 5. Find the ratio of the numbers of beads in Box L to the number of beads in Box M at first.
| |
Box L |
Box M |
| Before |
5x1 =
5 u |
7 u |
| Change |
- 3x1 =
- 3 u |
+ 3 u |
| After |
2x1 =
2 u |
|
Comparing Box L and
Box M in the end |
1x2 =
2 u |
5x2 =
10 u |
The number of beads in Box L in the end is repeated. Make the number of beads in Box L in the end the same. LCM of 2 and 1 is 2.
At first
Box L : Box M
5 : 7
Answer(s): 5 : 7
