There were some erasers in Packet E and Packet F. After Riordan transferred
15 of the erasers from Packet E to Packet F, the ratio of the number of erasers in Packet E to that in Packet F changed to 1 : 8. Find the ratio of the numbers of erasers in Packet F to the number of erasers in Packet E at first.
|
Packet E |
Packet F |
Before |
5x1 = 5 u |
31 u |
Change |
- 1x1 = - 1 u |
+ 1 u |
After |
4x1 = 4 u |
|
Comparing Packet E and Packet F in the end |
1x4 = 4 u |
8x4 = 32 u |
The number of erasers in Packet E in the end is repeated. Make the number of erasers in Packet E in the end the same. LCM of 4 and 1 is 4.
At first
Packet F : Packet E
31: 5
Answer(s): 31: 5