At a stall, the ratio of kiwis to papayas was 3 : 11. After Zoe bought four-fifths of the papayas, there was a total of 234 kiwis and papayas left at the stall. How many fruits were there at first?
| |
Kiwis |
Papayas |
Total |
Comparing kiwis
and papayas at first |
3x5 =
15 u |
11x5 =
55 u |
70 u |
Before |
|
5x11 =
55 u |
|
Change |
|
- 4x11 =
- 44 u |
|
After |
15 u |
1x11 =
11 u |
234 |
The number of papayas at first is repeated. Make the number of papayas at first the same. LCM of 11 and 5 is 55.
Total number of fruits left
= 15 u + 11 u
= 26 u
26 u = 234
1 u = 234 ÷ 26 = 9
Number of fruits at first
= 15 u + 55 u
= 70 u
= 70 x 9
= 630
Answer(s): 630
