Kathy and Opal collected cards. Kathy gave 60% of her cards to Opal and as a result, Opal's cards increased by 20%. If Kathy had 14 cards left, find the number of cards Opal should give to Kathy in the end so that both had an equal number of cards.
| |
Kathy
|
Opal |
Comparing the change
in Opal's cards
|
|
Before
|
5x1 =
5 u |
|
5x3 =
15u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
2x1 =
2 u
|
|
6x3 =
18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of cards that Opal had is repeated. Make the increase in the number of cards that Opal had the same. LCM of 3 and 1 = 3
2 u = 14
1 u = 14 ÷ 2 = 7
Number of cards that Opal had more than Kathy in the end
= 18 u - 2 u
= 16 u
Number of cards that Opal should give to Kathy so that both had an equal number of cards in the end
= 16 u ÷ 2
= 8 u
= 8 x 7
= 56
Answer(s): 56
