Jean and Min collected marbles. Jean gave 60% of her marbles to Min and as a result, Min's marbles increased by 20%. If Jean had 8 marbles left, find the number of marbles Min should give to Jean in the end so that both had an equal number of marbles.
| |
Jean
|
Min |
Comparing the change
in Min's marbles
|
|
Before
|
5x1 =
5 u |
|
5x3 =
15u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
2x1 =
2 u
|
|
6x3 =
18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of marbles that Min had is repeated. Make the increase in the number of marbles that Min had the same. LCM of 3 and 1 = 3
2 u = 8
1 u = 8 ÷ 2 = 4
Number of marbles that Min had more than Jean in the end
= 18 u - 2 u
= 16 u
Number of marbles that Min should give to Jean so that both had an equal number of marbles in the end
= 16 u ÷ 2
= 8 u
= 8 x 4
= 32
Answer(s): 32
