Xylia and Diana collected beads. Xylia gave 30% of her beads to Diana and as a result, Diana's beads increased by 10%. If Xylia had 28 beads left, find the number of beads Diana should give to Xylia in the end so that both had an equal number of beads.
| |
Xylia
|
Diana |
Comparing the change
in Diana's beads
|
|
Before
|
10x1 =
10 u |
|
10x3 =
30u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
7x1 =
7 u
|
|
11x3 =
33 u |
30% =
30100 =
31010% =
10100 =
110The increase in the number of beads that Diana had is repeated. Make the increase in the number of beads that Diana had the same. LCM of 3 and 1 = 3
7 u = 28
1 u = 28 ÷ 7 = 4
Number of beads that Diana had more than Xylia in the end
= 33 u - 7 u
= 26 u
Number of beads that Diana should give to Xylia so that both had an equal number of beads in the end
= 26 u ÷ 2
= 13 u
= 13 x 4
= 52
Answer(s): 52
