Shannon and Joelle collected coins. Shannon gave 30% of her coins to Joelle and as a result, Joelle's coins increased by 25%. If Shannon had 70 coins left, find the number of coins Joelle should give to Shannon in the end so that both had an equal number of coins.
|
Shannon
|
Joelle |
Comparing the change in Joelle's coins
|
Before
|
10x1 = 10 u |
|
4x3 = 12u |
Change
|
- 3x1 = - 3 u
|
+ 3x1 = + 3 u
|
+ 1x3 = + 3 u
|
After
|
7x1 = 7 u
|
|
5x3 = 15 u |
30% =
30100 =
31025% =
25100 =
14The increase in the number of coins that Joelle had is repeated. Make the increase in the number of coins that Joelle had the same. LCM of 3 and 1 = 3
7 u = 70
1 u = 70 ÷ 7 = 10
Number of coins that Joelle had more than Shannon in the end
= 15 u - 7 u
= 8 u
Number of coins that Joelle should give to Shannon so that both had an equal number of coins in the end
= 8 u ÷ 2
= 4 u
= 4 x 10
= 40
Answer(s): 40