Yoko and Kimberly collected beads. Yoko gave 30% of her beads to Kimberly and as a result, Kimberly's beads increased by 10%. If Yoko had 42 beads left, find the number of beads Kimberly should give to Yoko in the end so that both had an equal number of beads.

	Yoko	Kimberly	Comparing the change in Kimberly's beads
Before	10x1 = 10 u		10x3 = 30u
Change	- 3x1 = - 3 u	+ 3x1 = + 3 u	+ 1x3 = + 3 u
After	7x1 = 7 u		11x3 = 33 u

30% = ³⁰₁₀₀ = ³₁₀
10% = ¹⁰₁₀₀ = ¹₁₀

The increase in the number of beads that Kimberly had is repeated.  Make the increase in the number of beads that Kimberly had the same. LCM of 3 and 1 = 3

7 u = 42

1 u = 42 ÷ 7 = 6

Number of beads that Kimberly had more than Yoko in the end
= 33 u - 7 u
= 26 u

Number of beads that Kimberly should give to Yoko so that both had an equal number of beads in the end
= 26 u ÷ 2
= 13 u
= 13 x 6
= 78

Answer(s): 78