Winnie and Abi collected coins. Winnie gave 30% of her coins to Abi and as a result, Abi's coins increased by 10%. If Winnie had 49 coins left, find the number of coins Abi should give to Winnie in the end so that both had an equal number of coins.
| |
Winnie
|
Abi |
Comparing the change
in Abi's coins
|
|
Before
|
10x1 =
10 u |
|
10x3 =
30u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
7x1 =
7 u
|
|
11x3 =
33 u |
30% =
30100 =
31010% =
10100 =
110The increase in the number of coins that Abi had is repeated. Make the increase in the number of coins that Abi had the same. LCM of 3 and 1 = 3
7 u = 49
1 u = 49 ÷ 7 = 7
Number of coins that Abi had more than Winnie in the end
= 33 u - 7 u
= 26 u
Number of coins that Abi should give to Winnie so that both had an equal number of coins in the end
= 26 u ÷ 2
= 13 u
= 13 x 7
= 91
Answer(s): 91
