Barbara and Gem collected coins. Barbara gave 30% of her coins to Gem and as a result, Gem's coins increased by 10%. If Barbara had 35 coins left, find the number of coins Gem should give to Barbara in the end so that both had an equal number of coins.
| |
Barbara
|
Gem |
Comparing the change
in Gem's coins
|
|
Before
|
10x1 =
10 u |
|
10x3 =
30u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
7x1 =
7 u
|
|
11x3 =
33 u |
30% =
30100 =
31010% =
10100 =
110The increase in the number of coins that Gem had is repeated. Make the increase in the number of coins that Gem had the same. LCM of 3 and 1 = 3
7 u = 35
1 u = 35 ÷ 7 = 5
Number of coins that Gem had more than Barbara in the end
= 33 u - 7 u
= 26 u
Number of coins that Gem should give to Barbara so that both had an equal number of coins in the end
= 26 u ÷ 2
= 13 u
= 13 x 5
= 65
Answer(s): 65
