Wendy and Abi collected coins. Wendy gave 60% of her coins to Abi and as a result, Abi's coins increased by 20%. If Wendy had 12 coins left, find the number of coins Abi should give to Wendy in the end so that both had an equal number of coins.
| |
Wendy
|
Abi |
Comparing the change
in Abi's coins
|
|
Before
|
5x1 =
5 u |
|
5x3 =
15u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
2x1 =
2 u
|
|
6x3 =
18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of coins that Abi had is repeated. Make the increase in the number of coins that Abi had the same. LCM of 3 and 1 = 3
2 u = 12
1 u = 12 ÷ 2 = 6
Number of coins that Abi had more than Wendy in the end
= 18 u - 2 u
= 16 u
Number of coins that Abi should give to Wendy so that both had an equal number of coins in the end
= 16 u ÷ 2
= 8 u
= 8 x 6
= 48
Answer(s): 48
