Eva and Cathy collected stickers. Eva gave 60% of her stickers to Cathy and as a result, Cathy's stickers increased by 20%. If Eva had 20 stickers left, find the number of stickers Cathy should give to Eva in the end so that both had an equal number of stickers.
|
Eva
|
Cathy |
Comparing the change in Cathy's stickers
|
Before
|
5x1 = 5 u |
|
5x3 = 15u |
Change
|
- 3x1 = - 3 u
|
+ 3x1 = + 3 u
|
+ 1x3 = + 3 u
|
After
|
2x1 = 2 u
|
|
6x3 = 18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of stickers that Cathy had is repeated. Make the increase in the number of stickers that Cathy had the same. LCM of 3 and 1 = 3
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Cathy had more than Eva in the end
= 18 u - 2 u
= 16 u
Number of stickers that Cathy should give to Eva so that both had an equal number of stickers in the end
= 16 u ÷ 2
= 8 u
= 8 x 10
= 80
Answer(s): 80