Yen and Elyse collected coins. Yen gave 60% of her coins to Elyse and as a result, Elyse's coins increased by 20%. If Yen had 20 coins left, find the number of coins Elyse should give to Yen in the end so that both had an equal number of coins.
| |
Yen
|
Elyse |
Comparing the change
in Elyse's coins
|
|
Before
|
5x1 =
5 u |
|
5x3 =
15u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
2x1 =
2 u
|
|
6x3 =
18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of coins that Elyse had is repeated. Make the increase in the number of coins that Elyse had the same. LCM of 3 and 1 = 3
2 u = 20
1 u = 20 ÷ 2 = 10
Number of coins that Elyse had more than Yen in the end
= 18 u - 2 u
= 16 u
Number of coins that Elyse should give to Yen so that both had an equal number of coins in the end
= 16 u ÷ 2
= 8 u
= 8 x 10
= 80
Answer(s): 80
