Hazel and Jaslyn collected coins. Hazel gave 30% of her coins to Jaslyn and as a result, Jaslyn's coins increased by 10%. If Hazel had 77 coins left, find the number of coins Jaslyn should give to Hazel in the end so that both had an equal number of coins.

	Hazel	Jaslyn	Comparing the change in Jaslyn's coins
Before	10x1 = 10 u		10x3 = 30u
Change	- 3x1 = - 3 u	+ 3x1 = + 3 u	+ 1x3 = + 3 u
After	7x1 = 7 u		11x3 = 33 u

30% = ³⁰₁₀₀ = ³₁₀
10% = ¹⁰₁₀₀ = ¹₁₀

The increase in the number of coins that Jaslyn had is repeated.  Make the increase in the number of coins that Jaslyn had the same. LCM of 3 and 1 = 3

7 u = 77

1 u = 77 ÷ 7 = 11

Number of coins that Jaslyn had more than Hazel in the end
= 33 u - 7 u
= 26 u

Number of coins that Jaslyn should give to Hazel so that both had an equal number of coins in the end
= 26 u ÷ 2
= 13 u
= 13 x 11
= 143

Answer(s): 143