Cindy and Jade collected beads. Cindy gave 50% of her beads to Jade and as a result, Jade's beads increased by 30%. If Cindy had 36 beads left, find the number of beads Jade should give to Cindy in the end so that both had an equal number of beads.
| |
Cindy
|
Jade |
Comparing the change
in Jade's beads
|
|
Before
|
2x3 =
6 u |
|
10x1 =
10u |
|
Change
|
- 1x3 =
- 3 u
|
+ 1x3 =
+ 3 u
|
+ 3x1 =
+ 3 u
|
|
After
|
1x3 =
3 u
|
|
13x1 =
13 u |
50% =
50100 =
1230% =
30100 =
310The increase in the number of beads that Jade had is repeated. Make the increase in the number of beads that Jade had the same. LCM of 1 and 3 = 3
3 u = 36
1 u = 36 ÷ 3 = 12
Number of beads that Jade had more than Cindy in the end
= 13 u - 3 u
= 10 u
Number of beads that Jade should give to Cindy so that both had an equal number of beads in the end
= 10 u ÷ 2
= 5 u
= 5 x 12
= 60
Answer(s): 60
