Esther and Jean collected coins. Esther gave 60% of her coins to Jean and as a result, Jean's coins increased by 20%. If Esther had 18 coins left, find the number of coins Jean should give to Esther in the end so that both had an equal number of coins.
| |
Esther
|
Jean |
Comparing the change
in Jean's coins
|
|
Before
|
5x1 =
5 u |
|
5x3 =
15u |
|
Change
|
- 3x1 =
- 3 u
|
+ 3x1 =
+ 3 u
|
+ 1x3 =
+ 3 u
|
|
After
|
2x1 =
2 u
|
|
6x3 =
18 u |
60% =
60100 =
3520% =
20100 =
15The increase in the number of coins that Jean had is repeated. Make the increase in the number of coins that Jean had the same. LCM of 3 and 1 = 3
2 u = 18
1 u = 18 ÷ 2 = 9
Number of coins that Jean had more than Esther in the end
= 18 u - 2 u
= 16 u
Number of coins that Jean should give to Esther so that both had an equal number of coins in the end
= 16 u ÷ 2
= 8 u
= 8 x 9
= 72
Answer(s): 72
