Hazel had $345 less than Xylia. Xylia gave
23 of her money to Hazel. Hazel then gave 20% of her money to Xylia. In the end, Xylia had $171 less than Hazel. How much did Hazel have at first?
| |
Xylia |
Hazel |
| Comparing Xylia and Hazel at first |
345 more |
|
| Before |
3 u |
+ 345 |
3 u |
|
| Change 1 |
- 2 u |
- 230 |
+ 2 u |
+ 230 |
| After 1 |
1 u |
+ 115 |
5 u |
+ 230 |
| Change 2 |
+ 1 u |
+ 46 |
- 1 u |
- 46 |
| After 2 |
2 u |
+ 161 |
4 u |
+ 184 |
23 x 345= 230
345 - 230 = 115
20% x 5 u
=
20100 x 5 u
= 1 u
20% x 230
=
20100 x 230
= 46
230 - 46 = 184
115 + 46 = 161
If Xylia received another $171 in the end, Xylia and Hazel would have the same amount of money.
4 u + 184 = 2 u + 161 + 171
4 u - 2 u = 161 + 171 - 184
2 u = 148
1 u = 148 ÷ 2 = 74
Amount that Hazel had at first
= 3 u
= 3 x 74
= $222
Answer(s): $222
