Abi had $210 more than Pamela. Abi gave
23 of her money to Pamela. Pamela then gave 20% of her money to Abi. In the end, Abi had $102 less than Pamela. How much did Abi have at first?
| |
Abi |
Pamela |
| Comparing Abi and Pamela at first |
210 more |
|
| Before |
3 u |
+ 210 |
3 u |
|
| Change 1 |
- 2 u |
- 140 |
+ 2 u |
+ 140 |
| After 1 |
1 u |
+ 70 |
5 u |
+ 140 |
| Change 2 |
+ 1 u |
+ 28 |
- 1 u |
- 28 |
| After 2 |
2 u |
+ 98 |
4 u |
+ 112 |
23 x 210= 140
210 - 140 = 70
20% x 5 u
=
20100 x 5 u
= 1 u
20% x 140
=
20100 x 140
= 28
140 - 28 = 112
70 + 28 = 98
If Abi received another $102 in the end, Abi and Pamela would have the same amount of money.
4 u + 112 = 2 u + 98 + 102
4 u - 2 u = 98 + 102 - 112
2 u = 88
1 u = 88 ÷ 2 = 44
Amount that Abi had at first
= 3 u + 210
= 3 x 44 + 210
= 132 + 210
= $342
Answer(s): $342
