Raeann had $495 less than Marion. Marion gave
23 of her money to Raeann. Raeann then gave 20% of her money to Marion. In the end, Raeann had $103 more than Marion. How much did Raeann have at first?
| |
Marion |
Raeann |
| Comparing Marion and Raeann at first |
495 more |
|
| Before |
3 u |
+ 495 |
3 u |
|
| Change 1 |
- 2 u |
- 330 |
+ 2 u |
+ 330 |
| After 1 |
1 u |
+ 165 |
5 u |
+ 330 |
| Change 2 |
+ 1 u |
+ 66 |
- 1 u |
- 66 |
| After 2 |
2 u |
+ 231 |
4 u |
+ 264 |
23 x 495= 330
495 - 330 = 165
20% x 5 u
=
20100 x 5 u
= 1 u
20% x 330
=
20100 x 330
= 66
330 - 66 = 264
165 + 66 = 231
If Marion received another $103 in the end, Marion and Raeann would have the same amount of money.
4 u + 264 = 2 u + 231 + 103
4 u - 2 u = 231 + 103 - 264
2 u = 70
1 u = 70 ÷ 2 = 35
Amount that Raeann had at first
= 3 u
= 3 x 35
= $105
Answer(s): $105
