Gabriel had to paint some containers. On the first day, the number of containers he painted was 20% of the number of containers that he had not painted. One week later, he painted another 49 containers. As a result, the total number of painted containers became 23 more than
12 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x1 = 1 u |
5x1 = 5 u |
6x1 = 6 u |
Change |
+ 49 |
- 49 |
|
After |
1 u + 49 |
5 u - 49 |
6 u |
Comparing painted and not painted containers in the end |
1x3 + 23 = 3 u + 23 |
1x3 - 23 = 3 u - 23 |
2x3 = 6 u |
20% =
20100 =
15Painted : Not painted = 1 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 6 and 2 is 6.
The number of containers painted in the end is repeated.
3 u + 23 = 1 u + 49
3 u - 1 u = 49 - 23
2 u = 26
1 u = 26 ÷ 2 = 13
Number of more containers that were not painted than painted on the first day
= 5 u - 1 u
= 4 u
= 4 x 13
= 52
Answer(s): 52