Luis had to paint some boxes. On the first day, the number of boxes he painted was 10% of the number of boxes that he had not painted. One week later, he painted another 289 boxes. As a result, the total number of painted boxes became 16 more than
45 of the total number of boxes. How many more boxes were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
10x5 = 50 u |
11x5 = 55 u |
Change |
+ 289 |
- 289 |
|
After |
5 u + 289 |
50 u - 289 |
55 u |
Comparing painted and not painted boxes in the end |
4x11 + 16 = 44 u + 16 |
1x11 - 16 = 11 u - 16 |
5x11 = 55 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of boxes remains unchanged. Make the total number of boxes at first and in the end the same. LCM of 11 and 5 is 55.
The number of boxes painted in the end is repeated.
44 u + 16 = 5 u + 289
44 u - 5 u = 289 - 16
39 u = 273
1 u = 273 ÷ 39 = 7
Number of more boxes that were not painted than painted on the first day
= 50 u - 5 u
= 45 u
= 45 x 7
= 315
Answer(s): 315