Daniel had to paint some containers. On the first day, the number of containers he painted was 20% of the number of containers that he had not painted. One week later, he painted another 51 containers. As a result, the total number of painted containers became 16 more than
25 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
5x5 = 25 u |
6x5 = 30 u |
Change |
+ 51 |
- 51 |
|
After |
5 u + 51 |
25 u - 51 |
30 u |
Comparing painted and not painted containers in the end |
2x6 + 16 = 12 u + 16 |
3x6 - 16 = 18 u - 16 |
5x6 = 30 u |
20% =
20100 =
15Painted : Not painted = 1 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 6 and 5 is 30.
The number of containers painted in the end is repeated.
12 u + 16 = 5 u + 51
12 u - 5 u = 51 - 16
7 u = 35
1 u = 35 ÷ 7 = 5
Number of more containers that were not painted than painted on the first day
= 25 u - 5 u
= 20 u
= 20 x 5
= 100
Answer(s): 100