Paul had to paint some boxes. On the first day, the number of boxes he painted was 10% of the number of boxes that he had not painted. One week later, he painted another 452 boxes. As a result, the total number of painted boxes became 23 more than
45 of the total number of boxes. How many less boxes were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
10x5 = 50 u |
11x5 = 55 u |
Change |
+ 452 |
- 452 |
|
After |
5 u + 452 |
50 u - 452 |
55 u |
Comparing painted and not painted boxes in the end |
4x11 + 23 = 44 u + 23 |
1x11 - 23 = 11 u - 23 |
5x11 = 55 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of boxes remains unchanged. Make the total number of boxes at first and in the end the same. LCM of 11 and 5 is 55.
The number of boxes painted in the end is repeated.
44 u + 23 = 5 u + 452
44 u - 5 u = 452 - 23
39 u = 429
1 u = 429 ÷ 39 = 11
Number of less boxes that were painted than not painted on the first day
= 50 u - 5 u
= 45 u
= 45 x 11
= 495
Answer(s): 495