David had to paint some containers. On the first day, the number of containers he painted was 40% of the number of containers that he had not painted. One week later, he painted another 107 containers. As a result, the total number of painted containers became 17 more than
45 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
2x5 = 10 u |
5x5 = 25 u |
7x5 = 35 u |
Change |
+ 107 |
- 107 |
|
After |
10 u + 107 |
25 u - 107 |
35 u |
Comparing painted and not painted containers in the end |
4x7 + 17 = 28 u + 17 |
1x7 - 17 = 7 u - 17 |
5x7 = 35 u |
40% =
40100 =
25Painted : Not painted = 2 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 7 and 5 is 35.
The number of containers painted in the end is repeated.
28 u + 17 = 10 u + 107
28 u - 10 u = 107 - 17
18 u = 90
1 u = 90 ÷ 18 = 5
Number of less containers that were painted than not painted on the first day
= 25 u - 10 u
= 15 u
= 15 x 5
= 75
Answer(s): 75