Will had to paint some containers. On the first day, the number of containers he painted was 10% of the number of containers that he had not painted. One week later, he painted another 690 containers. As a result, the total number of painted containers became 27 more than
45 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
10x5 = 50 u |
11x5 = 55 u |
Change |
+ 690 |
- 690 |
|
After |
5 u + 690 |
50 u - 690 |
55 u |
Comparing painted and not painted containers in the end |
4x11 + 27 = 44 u + 27 |
1x11 - 27 = 11 u - 27 |
5x11 = 55 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 11 and 5 is 55.
The number of containers painted in the end is repeated.
44 u + 27 = 5 u + 690
44 u - 5 u = 690 - 27
39 u = 663
1 u = 663 ÷ 39 = 17
Number of more containers that were not painted than painted on the first day
= 50 u - 5 u
= 45 u
= 45 x 17
= 765
Answer(s): 765