Fred had to paint some containers. On the first day, the number of containers he painted was 40% of the number of containers that he had not painted. One week later, he painted another 33 containers. As a result, the total number of painted containers became 27 more than
12 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
2x2 = 4 u |
5x2 = 10 u |
7x2 = 14 u |
Change |
+ 33 |
- 33 |
|
After |
4 u + 33 |
10 u - 33 |
14 u |
Comparing painted and not painted containers in the end |
1x7 + 27 = 7 u + 27 |
1x7 - 27 = 7 u - 27 |
2x7 = 14 u |
40% =
40100 =
25Painted : Not painted = 2 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 7 and 2 is 14.
The number of containers painted in the end is repeated.
7 u + 27 = 4 u + 33
7 u - 4 u = 33 - 27
3 u = 6
1 u = 6 ÷ 3 = 2
Number of more containers that were not painted than painted on the first day
= 10 u - 4 u
= 6 u
= 6 x 2
= 12
Answer(s): 12