Fred had to paint some containers. On the first day, the number of containers he painted was 30% of the number of containers that he had not painted. One week later, he painted another 139 containers. As a result, the total number of painted containers became 27 more than
12 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
3x2 = 6 u |
10x2 = 20 u |
13x2 = 26 u |
Change |
+ 139 |
- 139 |
|
After |
6 u + 139 |
20 u - 139 |
26 u |
Comparing painted and not painted containers in the end |
1x13 + 27 = 13 u + 27 |
1x13 - 27 = 13 u - 27 |
2x13 = 26 u |
30% =
30100 =
310Painted : Not painted = 3 : 10
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 13 and 2 is 26.
The number of containers painted in the end is repeated.
13 u + 27 = 6 u + 139
13 u - 6 u = 139 - 27
7 u = 112
1 u = 112 ÷ 7 = 16
Number of less containers that were painted than not painted on the first day
= 20 u - 6 u
= 14 u
= 14 x 16
= 224
Answer(s): 224