Luis had to paint some boxes. On the first day, the number of boxes he painted was 10% of the number of boxes that he had not painted. One week later, he painted another 408 boxes. As a result, the total number of painted boxes became 18 more than
45 of the total number of boxes. How many more boxes were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
10x5 = 50 u |
11x5 = 55 u |
Change |
+ 408 |
- 408 |
|
After |
5 u + 408 |
50 u - 408 |
55 u |
Comparing painted and not painted boxes in the end |
4x11 + 18 = 44 u + 18 |
1x11 - 18 = 11 u - 18 |
5x11 = 55 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of boxes remains unchanged. Make the total number of boxes at first and in the end the same. LCM of 11 and 5 is 55.
The number of boxes painted in the end is repeated.
44 u + 18 = 5 u + 408
44 u - 5 u = 408 - 18
39 u = 390
1 u = 390 ÷ 39 = 10
Number of more boxes that were not painted than painted on the first day
= 50 u - 5 u
= 45 u
= 45 x 10
= 450
Answer(s): 450