Cole had to paint some containers. On the first day, the number of containers he painted was 40% of the number of containers that he had not painted. One week later, he painted another 56 containers. As a result, the total number of painted containers became 26 more than
12 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
2x2 = 4 u |
5x2 = 10 u |
7x2 = 14 u |
Change |
+ 56 |
- 56 |
|
After |
4 u + 56 |
10 u - 56 |
14 u |
Comparing painted and not painted containers in the end |
1x7 + 26 = 7 u + 26 |
1x7 - 26 = 7 u - 26 |
2x7 = 14 u |
40% =
40100 =
25Painted : Not painted = 2 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 7 and 2 is 14.
The number of containers painted in the end is repeated.
7 u + 26 = 4 u + 56
7 u - 4 u = 56 - 26
3 u = 30
1 u = 30 ÷ 3 = 10
Number of more containers that were not painted than painted on the first day
= 10 u - 4 u
= 6 u
= 6 x 10
= 60
Answer(s): 60