Liam had to paint some containers. On the first day, the number of containers he painted was 40% of the number of containers that he had not painted. One week later, he painted another 93 containers. As a result, the total number of painted containers became 21 more than
25 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
2x5 = 10 u |
5x5 = 25 u |
7x5 = 35 u |
Change |
+ 93 |
- 93 |
|
After |
10 u + 93 |
25 u - 93 |
35 u |
Comparing painted and not painted containers in the end |
2x7 + 21 = 14 u + 21 |
3x7 - 21 = 21 u - 21 |
5x7 = 35 u |
40% =
40100 =
25Painted : Not painted = 2 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 7 and 5 is 35.
The number of containers painted in the end is repeated.
14 u + 21 = 10 u + 93
14 u - 10 u = 93 - 21
4 u = 72
1 u = 72 ÷ 4 = 18
Number of less containers that were painted than not painted on the first day
= 25 u - 10 u
= 15 u
= 15 x 18
= 270
Answer(s): 270