Ken had to paint some containers. On the first day, the number of containers he painted was 10% of the number of containers that he had not painted. One week later, he painted another 342 containers. As a result, the total number of painted containers became 30 more than
45 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
10x5 = 50 u |
11x5 = 55 u |
Change |
+ 342 |
- 342 |
|
After |
5 u + 342 |
50 u - 342 |
55 u |
Comparing painted and not painted containers in the end |
4x11 + 30 = 44 u + 30 |
1x11 - 30 = 11 u - 30 |
5x11 = 55 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 11 and 5 is 55.
The number of containers painted in the end is repeated.
44 u + 30 = 5 u + 342
44 u - 5 u = 342 - 30
39 u = 312
1 u = 312 ÷ 39 = 8
Number of less containers that were painted than not painted on the first day
= 50 u - 5 u
= 45 u
= 45 x 8
= 360
Answer(s): 360