Paul had to paint some containers. On the first day, the number of containers he painted was 20% of the number of containers that he had not painted. One week later, he painted another 37 containers. As a result, the total number of painted containers became 23 more than
34 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x2 = 2 u |
5x2 = 10 u |
6x2 = 12 u |
Change |
+ 37 |
- 37 |
|
After |
2 u + 37 |
10 u - 37 |
12 u |
Comparing painted and not painted containers in the end |
3x3 + 23 = 9 u + 23 |
1x3 - 23 = 3 u - 23 |
4x3 = 12 u |
20% =
20100 =
15Painted : Not painted = 1 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 6 and 4 is 12.
The number of containers painted in the end is repeated.
9 u + 23 = 2 u + 37
9 u - 2 u = 37 - 23
7 u = 14
1 u = 14 ÷ 7 = 2
Number of less containers that were painted than not painted on the first day
= 10 u - 2 u
= 8 u
= 8 x 2
= 16
Answer(s): 16