Ken had to paint some containers. On the first day, the number of containers he painted was 20% of the number of containers that he had not painted. One week later, he painted another 286 containers. As a result, the total number of painted containers became 26 more than
35 of the total number of containers. How many less containers were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x5 = 5 u |
5x5 = 25 u |
6x5 = 30 u |
Change |
+ 286 |
- 286 |
|
After |
5 u + 286 |
25 u - 286 |
30 u |
Comparing painted and not painted containers in the end |
3x6 + 26 = 18 u + 26 |
2x6 - 26 = 12 u - 26 |
5x6 = 30 u |
20% =
20100 =
15Painted : Not painted = 1 : 5
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 6 and 5 is 30.
The number of containers painted in the end is repeated.
18 u + 26 = 5 u + 286
18 u - 5 u = 286 - 26
13 u = 260
1 u = 260 ÷ 13 = 20
Number of less containers that were painted than not painted on the first day
= 25 u - 5 u
= 20 u
= 20 x 20
= 400
Answer(s): 400