Gabriel had to paint some boxes. On the first day, the number of boxes he painted was 10% of the number of boxes that he had not painted. One week later, he painted another 110 boxes. As a result, the total number of painted boxes became 20 more than
12 of the total number of boxes. How many less boxes were painted than unpainted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x2 = 2 u |
10x2 = 20 u |
11x2 = 22 u |
Change |
+ 110 |
- 110 |
|
After |
2 u + 110 |
20 u - 110 |
22 u |
Comparing painted and not painted boxes in the end |
1x11 + 20 = 11 u + 20 |
1x11 - 20 = 11 u - 20 |
2x11 = 22 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of boxes remains unchanged. Make the total number of boxes at first and in the end the same. LCM of 11 and 2 is 22.
The number of boxes painted in the end is repeated.
11 u + 20 = 2 u + 110
11 u - 2 u = 110 - 20
9 u = 90
1 u = 90 ÷ 9 = 10
Number of less boxes that were painted than not painted on the first day
= 20 u - 2 u
= 18 u
= 18 x 10
= 180
Answer(s): 180