Howard had to paint some containers. On the first day, the number of containers he painted was 10% of the number of containers that he had not painted. One week later, he painted another 96 containers. As a result, the total number of painted containers became 15 more than
12 of the total number of containers. How many more containers were unpainted than painted on the first day?
|
Painted |
Not painted |
Total |
Before
|
1x2 = 2 u |
10x2 = 20 u |
11x2 = 22 u |
Change |
+ 96 |
- 96 |
|
After |
2 u + 96 |
20 u - 96 |
22 u |
Comparing painted and not painted containers in the end |
1x11 + 15 = 11 u + 15 |
1x11 - 15 = 11 u - 15 |
2x11 = 22 u |
10% =
10100 =
110Painted : Not painted = 1 : 10
The total number of containers remains unchanged. Make the total number of containers at first and in the end the same. LCM of 11 and 2 is 22.
The number of containers painted in the end is repeated.
11 u + 15 = 2 u + 96
11 u - 2 u = 96 - 15
9 u = 81
1 u = 81 ÷ 9 = 9
Number of more containers that were not painted than painted on the first day
= 20 u - 2 u
= 18 u
= 18 x 9
= 162
Answer(s): 162