Shannon and Jaslyn had a total of 60 stamps. Jaslyn gave ¹₃ of her stamps to Shannon. In return, Shannon gave ¹₆ of the total number of stamps that she had to Jaslyn. In the end, each girl had the same number of stamps. How many stamps did Shannon have at first?

	Shannon	Jaslyn	Total
Before 1	?	3 u	60
Change 1	+ 1 u	- 1 u
After 1	36	2 u	60
Before 2	6 p	2 u	60
Change 2	- 1 p	+ 1 p
After 2	5 p (30)	30	60

Since Jaslyn gave some stamps to Shannon and Shannon then gave some stamps to Jaslyn, it is an internal transfer of stamps between the two girls. So, the total number of stamps remains unchanged.

Number of stamps that Jaslyn and Shannon each had in the end is the same.

Number of stamps that Shannon had in the end
= 60 ÷ 2
= 30

Number of stamps that Shannon had in the end = 5 p

5 p = 30

1 p = 30 ÷ 5 = 6

Number of stamps that Shannon had after receiving some stamps from Jaslyn
= 6 p
= 6 x 6
= 36

Number of stamps that Jaslyn had after giving to Shannon
= 60 - 36
= 24

2 u = 24

1 u = 24 ÷ 2 = 12

Number of stamps that Jaslyn had at first
= 3 u
= 3 x 12
= 36

Number of stamps that Shannon had at first
= 60 - 36
= 24

Answer(s): 24