Hazel and Zoe had a total of 50 stickers. Zoe gave
13 of her stickers to Hazel. In return, Hazel gave
16 of the total number of stickers that she had to Zoe. In the end, each girl had the same number of stickers. How many stickers did Hazel have at first?
|
Hazel |
Zoe |
Total |
Before 1 |
? |
3 u |
50 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
30 |
2 u |
50 |
Before 2 |
6 p |
2 u |
50 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
5 p (25) |
25 |
50 |
Since Zoe gave some stickers to Hazel and Hazel then gave some stickers to Zoe, it is an internal transfer of stickers between the two girls. So, the total number of stickers remains unchanged.
Number of stickers that Zoe and Hazel each had in the end is the same.
Number of stickers that Hazel had in the end
= 50 ÷ 2
= 25
Number of stickers that Hazel had in the end = 5 p
5 p = 25
1 p = 25 ÷ 5 = 5
Number of stickers that Hazel had after receiving some stickers from Zoe
= 6 p
= 6 x 5
= 30
Number of stickers that Zoe had after giving to Hazel
= 50 - 30
= 20
2 u = 20
1 u = 20 ÷ 2 = 10
Number of stickers that Zoe had at first
= 3 u
= 3 x 10
= 30
Number of stickers that Hazel had at first
= 50 - 30
= 20
Answer(s): 20